I came upon a couple of equations and decided to use them on a proven pinhole camera I own. This camera takes really "sharp" images for a pinhole camera. I always guessed that I was getting these good images as a result of hitting the sweet spot, the Airy disk. The camera is a 4x5 made from a cigar box. These are the specifications:
Camera: 4x5
f/250
Focal Length = 90mm
Pinhole = Laser made and purchased
Pinhole Diameter Size = .350mm
Pinhole Material Thickness = .025 (actual specs are .019 - .050)
I'll post a photo sample if anyone is interested, but I am more interested in the following equations that were obtained from an article titled, THE COMPREHENSIVE TECH GUIDE TO PINHOLE PHOTOGRAPHY, postedMarch 6, 2013 by Udi Tirosh. Mr. Tirosh, if you are here, thank you for your post.
view angle = tan-1( (d/2)/(t/2) ) x 2 {my solution was 172}
image diameter (mm) = 2 x focal length x tan ((View angle)/2) {my solution was 2502}
Actually, the second equation interested me most. That said, I needed the first to come up with the second. When I obtained the result for the "image diameter" and compared it to the film diagonal (163) for my 4x5, I was struck by the difference in size. This made sense as the centermost portion of the light was what was captured, the Airy disk. Now, just so everyone understands. I am not making a point and calling this fact. Far from it. I am asking, is this correct? Am I missing something?
One last thing. I am a math dingus and often times I am really out of my depth. In my later years I have grown to like math and wish I had listened in school. I like this sort of math, but as I said, out of my depth.
Best,
Henry